3d^2-4d+1=

Solution for 3d^2-4d+1= equation:

Simplifying
3d2 + -4d + 1 = 0

Reorder the terms:
1 + -4d + 3d2 = 0

Solving
1 + -4d + 3d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(1 + -3d)(1 + -1d) = 0

Subproblem 1
Set the factor '(1 + -3d)' equal to zero and attempt to solve:

Simplifying
1 + -3d = 0

Solving
1 + -3d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3d = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3d = 0 + -1
-3d = 0 + -1

Combine like terms: 0 + -1 = -1
-3d = -1

Divide each side by '-3'.
d = 0.3333333333

Simplifying
d = 0.3333333333
Subproblem 2
Set the factor '(1 + -1d)' equal to zero and attempt to solve:

Simplifying
1 + -1d = 0

Solving
1 + -1d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1d = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1d = 0 + -1
-1d = 0 + -1

Combine like terms: 0 + -1 = -1
-1d = -1

Divide each side by '-1'.
d = 1

Simplifying
d = 1
Solution
d = {0.3333333333, 1}